A police car takes off from rest reaching a speed of 78km/hr at 5.99 seconds. What is the average acceleration in (m/s)^2 of the car?
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initial time = 0 , end time = 5.99 seconds
initial velocity = 0 , end velocity = 78 * 5/ 18 = 21.667 (m/s)
a = deltaV / delta t , a = Vend - V0 / Tend - T0
acceleration = change in velocity / change in time
a = 21.667 - 0 / 5.99 -0 = 3.617 m/s^2
= 3.167 m/s^2
hope this helps
initial velocity = 0 , end velocity = 78 * 5/ 18 = 21.667 (m/s)
a = deltaV / delta t , a = Vend - V0 / Tend - T0
acceleration = change in velocity / change in time
a = 21.667 - 0 / 5.99 -0 = 3.617 m/s^2
= 3.167 m/s^2
hope this helps