A force pointing in the x direction is given by F=ax^(3/2), where a=0.55N/m^(3/2). Find the work done by this

Favorites|Homepage
Subscriptions | sitemap

HOME > > A force pointing in the x direction is given by F=ax^(3/2), where a=0.55N/m^(3/2). Find the work done by this

A force pointing in the x direction is given by F=ax^(3/2), where a=0.55N/m^(3/2). Find the work done by this

[From: ] [author: ] [Date: 12-07-07] [Hit: ]

55N/m^(3/2). Find the work done by this force as it acts on an object moving from 0 m to 16m.-I will take a stab by saying you need to integrate your force function with respect to x as W = F.x and the force is dependent on the distance.gives you (2/5)ax^(5/2) = (2/5)*0.55*16^(5/2) = 225.......

A force pointing in the x direction is given by F=ax^(3/2), where a=0.55N/m^(3/2). Find the work done by this force as it acts on an object moving from 0 m to 16m.

-

I will take a stab by saying you need to integrate your force function with respect to x as W = F.x and the force is dependent on the distance.

gives you (2/5)ax^(5/2) = (2/5)*0.55*16^(5/2) = 225.28 joules

1

keywords: pointing,ax,this,force,is,given,work,direction,in,Find,0.55,done,by,where,the,A force pointing in the x direction is given by F=ax^(3/2), where a=0.55N/m^(3/2). Find the work done by this

New

Hot