Hardy-Weinberg problems- HELP

Can someone help me figure this out, a Native America tribe of central Arizona, Woolf and Dukepoo(1959) found 26 albino individuals in a total population of 6000. This form of albinism is controlled by a single gene with two alleles: albinism is recessive to normal skin coloration.


1)Calculate the expected allele frequencies and genotype frequencies if the population were in Hardy-Weinberg equilibrium.



2) How many of the Hopi are estimated to be normally pigmented carriers of the recessive albino allele?

1) Hardy-Weinberg Equilibrium is based on two equations:
p + q =1
p^2 + 2pq + q^2 = 1

p = frequency of dominant allele
q = frequency of recessive allele
p^2 = frequency of homozygote dominant
2pq = frequency of heterozygote
q^2 = frequency of homozygote recessive

All numbers are rounded to 4 significant figures.

q^2 = 26/6000 = 0.004333
q = Squareroot(0.004333)
q = 0.06583
p = 1 - 0.06583 = 0.9342
p^2 = (0.9342)^2 = 0.8727
2pq = 2(0.9342)(0.06583)
2pq = 0.1230

And to double check:
2pq = 1 - 0.8727 - 0.004333
2pq = 0.1230

2) The normally pigmented carriers are heterozyotes. The proportion of heterozygotes is 0.1230. The number of heterozyogtes = 0.1230 x 6000 = 738 (nearest whole number)