How to do a 6:6:2:2 ratio? How do I figure out the genotypes of the male and female parents? HELP!!!!!!!!!

In the bobcat, the dominant allele R causes solid tail color, and the recessive allele r results in white spots on a colored background. The black coat color allele B is dominant to the brown allele b. A mating between a black colored solid tailed male bobcat and a brown colored solid tailed female bobcat produced 16 offspring with the following tail phenotypes: 6 black solid, 6 brown solid, 2 black spotted, and 2 brown spotted.
The questions are:
A) What are the most likely genotypes of the male and female parents?
B) What is the probability of the 17th offspring of the original parents being brown with a spotted tail?

Yes,
black or brown : 50% chance (8/16): Bb and bb genotypes in parents
Spotted or solid: a 75% and 25% chance respectively. Rr and Rr genotypes in the parents.

Crossing these Bb Rr and bb Rr parent genotypes results in given genotype frequencies.

You are making this harder than it is.

First, you have a 3:3:1:1 ratio.

You take it one trait at a time.

So.... how many black to brown are there? It turns out it's 8:8 or 1:1. A test cross gives you a 1:1 ratio.

Now for the tail color..... 12 solid to 4 spotted, a 3:1 ratio. That's a simple heterozygous x heterozygous cross.

You can figure out the rest.