CO2 produced by astronauts on space mission needs to be eliminated from the air as it is detrimental to the astronauts. Engineers created a device that reacts the CO2 with LiOH to produce Li2CO3. Columbia Mission has failed and a rescue mission has been organized. If there is only 213 kg of LiOH on board, how long does the rescue crew have to save the 7 astronauts before the LiOH runs out? (1kg CO2 produced/day/astronaut) PLEASE PLEASE SHOW all your calculations and works PLEASEEE. THX FOR YOUR VALUABLE TIME! peace!
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CO2 + 2 LiOH → H2O + Li2CO3
(213 kg LiOH) / (23.9486 g LiOH/mol) x (1/2) x (44.0096 g/mol) = 195.7 kg CO2
(195.7 kg)/ (7 kg/day) = 28 days
(213 kg LiOH) / (23.9486 g LiOH/mol) x (1/2) x (44.0096 g/mol) = 195.7 kg CO2
(195.7 kg)/ (7 kg/day) = 28 days
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The 1 in the 1/2 comes from the number of moles of CO2 in the balanced equation. The 2 comes from the number of moles of LiOH there. Another way of putting it is that the number of moles of CO2 reacting is 1/2 the number of moles of LiOH reacting.
44.0096 is the molecular mass of CO2.
44.0096 is the molecular mass of CO2.
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