What mass of solid potassium oxalate (K2C2O4), when dissolved in an acidic solution, would be titrated by exactly 25.0 mL of 0.0347 M potassium permanganate (KMnO4) solution? (Mn2+ ions and carbon dioxide are produced in the reaction.)
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0.0347M KMnO4 x 0.025L = 8.68x10^-4moles
the equation = 2KMnO4 + 8H2SO4 + 5K2C2O4 --> 6K2SO4 + 2MnSO4 + 8H2O + 10CO2
mass K2C2O4 = 8.68x10^-4moles KMnO4 x (5K2C2O4 / 2KMnO4) x 166g/mole = 0.36g
the equation = 2KMnO4 + 8H2SO4 + 5K2C2O4 --> 6K2SO4 + 2MnSO4 + 8H2O + 10CO2
mass K2C2O4 = 8.68x10^-4moles KMnO4 x (5K2C2O4 / 2KMnO4) x 166g/mole = 0.36g