H2S + CO -----> CH3CO2H + S8
And please explain it to me! Thanks!
And please explain it to me! Thanks!
-
The answer by M has a spurious factor of 4 in it. Here's the correct answer:
Balance the H and the S at the same time:
2H2S + CO -----> CH3CO2H + (1/4)S8
Balance the C and the O at the same time:
2H2S + 2CO -----> CH3CO2H + (1/4)S8
Clear the fraction:
8H2S + 8CO -----> 4CH3CO2H + S8
Balance the H and the S at the same time:
2H2S + CO -----> CH3CO2H + (1/4)S8
Balance the C and the O at the same time:
2H2S + 2CO -----> CH3CO2H + (1/4)S8
Clear the fraction:
8H2S + 8CO -----> 4CH3CO2H + S8
-
32H2S + 32CO -----> 16CH3CO2H + 4S8