Calculate the number of moles of Hydrogen in 0.15mol of CH4
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Calculate the number of moles of Hydrogen in 0.15mol of CH4

[From: ] [author: ] [Date: 11-10-18] [Hit: ]
0.15mol CH4 contains 0.15*4 = 0.Question from me: why did you multiply twice by 0.15?0.......
please answer with explanations, i don't want a whole bunchof random numbers :(
any answer is fine, i'll reward with the best explanations.

I think the answer is:
There's 4 H so
4 x 0.15 = 0.6
0.15 x 0.6 = 0.09
so therefore there are 0.09mol of H in 0.15mol of CH4

Is that how you do it?
If it's right, can you please calculate the number of moles of Al in 0.5mol of Al(OH)3?

thank you so much. i appreciate it.
i can ask my teacher but she wont be teaching us until 2 more days so i would like to find out now.

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The molecule is CH4 = count the H atoms in 1 molecule CH4: 4 Right?
So you must expect the final answer to be greater than the moles of CH4. In fact 4 times greater:
Calculation:
1 molecule CH4 contains 4 atoms H
1 mol of CH4 contains 4 mol H atoms
0.15mol CH4 contains 0.15*4 = 0.6 mol H atoms

Question from me: why did you multiply twice by 0.15?

Second question - exactly the same method:
1 molecule Al (OH)3 contains 1 atom Al
1 mol Al(OH)3 contains 1 mol Al atoms
0.5mol Al(OH)3 contains 0.5 mol Al atoms.

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0.6 mol of Hydrogen and 0.15 mol of Carbon in 0.15mol of CH4
0.5 mol of Al(OH)3 corresponds to 0.5 mol of Al, 1.5 mol of Oxygen and 1.5 mol of Hydrogen

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First, I would like to state that I have not gotten to the point in my personal studies of chemistry. When I supply this answer, I am only guessing.

I believe that for one mole of CH4, there is 1 mole of carbon and 4 moles of hydrogen. If you are only concerned with the hydrogen, you can completely disregard the carbon.

Simply divide the amount of moles by 100 (to make it one percent), and then multiply that by fifteen (to make it fifteen percent).

You can do this exactly the same way with another element. Just get fifteen percent of the number of moles of that element in your formula.

To get it in grams, multiply your result by the atomic mass of the element. So for hydrogen, that would be 1.008 (approximately)
Again, I would like to state that I am only guessing.
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