in the reaction Mg+2HCl ---> MgCl2+H2, if 4.00 grams of Mg are completely comsumed,
a) how many grams of MgCl2 will be produced?
b)will a 2.0 Liter balloon be large enough to contain all of the hydrogen produced?
Please explain!
a) how many grams of MgCl2 will be produced?
b)will a 2.0 Liter balloon be large enough to contain all of the hydrogen produced?
Please explain!
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Mg + 2 HCl → MgCl2 + H2
a)
(4.00 g Mg) / (24.3051 g Mg/mol) x (1/1) x (95.2115 g MgCl2/mol)) = 15.7 g MgCl2
b)
(4.00 g Mg) / (24.3051 g Mg/mol) x (1/1) x (22.4 L/mol) = 3.69 L H2, so no, the balloon is too small
a)
(4.00 g Mg) / (24.3051 g Mg/mol) x (1/1) x (95.2115 g MgCl2/mol)) = 15.7 g MgCl2
b)
(4.00 g Mg) / (24.3051 g Mg/mol) x (1/1) x (22.4 L/mol) = 3.69 L H2, so no, the balloon is too small
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The 1/1 in a) shows that 1 mole of MgCl2 is produced for each 1 mole of Mg reacted.
The 1/1 in b) shows that 1 mole of H2 is produced for each 1 mole of Mg reacted.
The 1/1 in b) shows that 1 mole of H2 is produced for each 1 mole of Mg reacted.
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