Le chatelier's principle help
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Le chatelier's principle help

[From: ] [author: ] [Date: 12-04-04] [Hit: ]
the reaction proceeds to the right, and NH3 will increase while N2 and H2 will decrease4. if H2 is removed, the reaction will go towards the left side in order to make more H2 to maintain the equilibrium,......

3. Same as above; if you increase one side, you must decrease the other.

4. If H2 is decreased, then the equilibrium will try to act against this by increasing H2. So

2NH3(g) + 22.0 kcal -> N2(g) + 3H2(g) to make more H2.

That means more N2 and H2 are produced, but NH3 is decreased for this to happen.

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1. yes both N2 and H2 increase, you can think of it like you are putting heat in, and according to the reaction, it's on the right side, so you are combining heat with NH3 to make N2 and H2; so NH3 decrease while N2 and H2 increase

2. when pressure increase, the reaction goes toward the side with the least number of moles of compounds, in the reaction, the left side has 4 moles while the right side has 2 moles, therefore the reaction will proceed to the right and NH3 will increase while N2 and H2 will decrease.

3. that's not it; when you are removing a compound, the reaction will react towards that side to make more of it in order to maintain the equilibrium, therefore when NH3 is removed, the reaction proceeds to the right, and NH3 will increase while N2 and H2 will decrease

4. if H2 is removed, the reaction will go towards the left side in order to make more H2 to maintain the equilibrium, so NH3 will decrease while H2 and N2 will increase
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