How many grams of ammonium nitrite are necessary to form 0.595 moles water
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How many grams of ammonium nitrite are necessary to form 0.595 moles water

[From: ] [author: ] [Date: 12-04-19] [Hit: ]
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ammonium nitrite (aq) nitrogen (g) + water (l)

___grams ammonium nitrite?

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NH4NO2 → N2 + 2 H2O

(0.595 mol H2O) x (1 mol NH4NO2 / 2 mol H2O) x (64.04409 g NH4NO2/mol) = 19.1 g NH4NO2
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