Chemistry Molarity.........

If the Mass for C12H22O11 is 60.38 g and the Molarity is 0.150 M. what is the solute (Mol), and the Volume by mL for C12H22O11 ?

Moles of C12H22O11 = 60.38/342 = 0.176
Vol. for 0.150 M C12H22O11 = 0.176 x 1000/0.150 = 1173 mL

Molecular Weight of C12H22O11 = 342.3 g/mol

Mols of solute- 60.38g / 342.3 g/mol = .1764 mol

Molarity (M)= mol/L

0.150 mol/L (M) / 0.1764 mol = 0.85034 L = 850.34 mL

Final Answer= .1764 mol C12H22O11, 850.34 mL