What is the concentration of sulfate ions in 0.010 M Al2(SO4)3 (aq)

[From: ] [author: ] [Date: 12-04-19] [Hit: ]

[Al2(SO4)3] = 0.010 mol Al2(SO4)3 / L
Al2(SO4)3 (aq) --> 2Al3+ (aq) + 3SO4 2- (aq)

sulfate
[SO4 2-] = ?

Thanks!

One mole contains 3 moles of SO4 -ions therefore 0.010 moles contain 0,030 moles of SO4^2- ions

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