A 15.6 gram sample of xenon gas has a volume of 860 milliliters at a pressure of 3.01 atm. The temperature of the Xe gas sample is ______ degrees C.
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15.6 g Xe * (1 mol Xe/131.3g) = 0.119 mol Xe
PV = nRT
(3.01 atm)(0.860 L) = (0.119 mol)(0.0821 L atm/K mol) * T
T = 265K
T = 265K - 273K = -8 degrees C (you lose 2 sig figs because of the subtraction).
PV = nRT
(3.01 atm)(0.860 L) = (0.119 mol)(0.0821 L atm/K mol) * T
T = 265K
T = 265K - 273K = -8 degrees C (you lose 2 sig figs because of the subtraction).