Solve for triangle ABC given that a=12, b=15, and c=20
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Solve for triangle ABC given that a=12, b=15, and c=20

[From: ] [author: ] [Date: 12-05-14] [Hit: ]
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how do you find the angles using law of sine and cosine?

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Since you know all the lengths, the law of cosines is what you want to use:

c^2 = a^2 + b^2 - 2ab cos C
=> cos C = (a^2 + b^2 - c^2) / 2ab
= (144 + 225 - 400) / 360
= -31/360
=> C = cos^-1 (-31/360) = 94.9 degrees

Find angles A and B in the same way
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