If I have a sine wave with an amp of say 4 V, BUT it is offset with DC to 1V (meaning the Top will be 5V, and the bottom -3V) - what will the avarage voltage be?
I am reffering to the 2/pi formula (0,637 * Upk) and how I can use it here.
Many thanks in advance!
I am reffering to the 2/pi formula (0,637 * Upk) and how I can use it here.
Many thanks in advance!
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Average equals 1 volt, as the sine wave average is zero.
Rectified how? A simple single diode, a bridge? In which direction is the diode pointing?
And what does "rectified mean average" mean? I'll assume you mean the average voltage of the rectified signal.
A single diode, pointing towards the load, will produce a voltage that varies from zero to +5v, minus the diode drop. The wave shape is the top 5/8 of the sine wave. To get the actual average value, you have to calculate the zero crossings and integrate the function.
Other diode connections will produce different waveforms.
Rectified how? A simple single diode, a bridge? In which direction is the diode pointing?
And what does "rectified mean average" mean? I'll assume you mean the average voltage of the rectified signal.
A single diode, pointing towards the load, will produce a voltage that varies from zero to +5v, minus the diode drop. The wave shape is the top 5/8 of the sine wave. To get the actual average value, you have to calculate the zero crossings and integrate the function.
Other diode connections will produce different waveforms.
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yes of course that is what is meant by average. on the sine wave only.