Solve: log2 (x) + log2 (x + 1) = 1
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Solve: log2 (x) + log2 (x + 1) = 1

[From: ] [author: ] [Date: 11-05-16] [Hit: ]
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log2 (x) + log2 (x + 1) = 1
log2 [(x)(x+1)] = 1
log2 (x^2 + x) = 1
x^2 + x = 2^1
x^2 + x = 2
x^2 + x - 2 = 0
(x + 2) ( x -1) = 0

x = -2 or x = 1

-
x = 1
1
keywords: log,Solve,Solve: log2 (x) + log2 (x + 1) = 1
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