Can someone show me how to solve this equation

8(2t+5t) over 7, + 2(3t+t) over 4 = 8(2t+t)+28

[8(2t + 5t) / 7] + [2(3t + t) / 4] = 8(2t + t) + 28
[8(7t) / 7] + [2(4t) / 4] = 8(3t) + 28
[(8)(7)(t) / 7] + [(2)(4)(t) / 4] = 24t + 28
[8t] + [2t] = 24t + 28
10t = 24t + 28
24t - 10t = -28
14t = -28
t = -28 / 14
t = -2