8. srry idk the restriction stuff.Well there u go. I gave u half. Hope this helps!-1.......
and the second answer is 6x^2+21x+18.
6. idk
7.(3x)^2+2(3x)-24 so (3x+6)(3x-4) divide first one by 3 and second by 1 and so ur answer is (x+2)(3x-4)
And the second answer is (3x)^2-5(3x)+36 so (3x-9)(3x+4) divide first by 3. Answer is (x-3)(3x+4).
8. srry idk the restriction stuff.
Well there u go. I gave u half. Hope this helps!
1. (x+3)/(x-3)
2. x cannot = 2 or 3
3. =[(a-4)(a-3)]/[(a-4)(a+4) = (a-3)/(a-4)
4. a cannot = +/- 4
5. =(3x -6)(2x+3)/[(3x+6)(3+2x)] = (3x-6)(/3x+6)
6. x cannot = -2 or - 3/2
7. Do the rest yourself now
1).
(x - 2)(x + 3)/(x - 3)(x - 2)
= (x + 3)/(x - 3)
2).
x ≠ 3
3).
(a2 - a - 12)/(a2 - 16)
= (a - 4)(a + 3)/(a - 4)(a + 4)
= (a + 3)/(a + 4)
4).
a ≠ -4
5).
(6x2 - 3x - 18)/(3x + 6)(3 + 2x)
= 3(x - 2)(2x + 3)/3(x + 2)(2x + 3)
= (x - 2)/(x + 2)
6).
x ≠ -2
7).
(3x2 + 2x - 8)/(12 - 5x - 3x2)
= (x + 2)(3x - 4)/-(x + 3)(3x - 4)
= -(x + 2))/(x + 3)
8).
x ≠ -3
