you have to rewrite this equation: 2(y^2)x4y+5=0
at first i thought it could be rewritten into a parabola or hyperbola but now i dont know. thanks for the help!
at first i thought it could be rewritten into a parabola or hyperbola but now i dont know. thanks for the help!

2y²  x  4y + 5 = 0
There is a only one squared variable, so it is a parabola.
The squared variable is y², not x², so the parabola is horizontal.
Put equation into vertex form for horizontal parabola:
x = a(y−k)² + h
Regroup terms
x = 2y²  4y + 5
Factor out the leading coefficient
x = 2(y²  2y) + 5
Complete the square
x = 2(y²  2y + (1)²) + 5  2(1)²
x = 2(y  1)² + 3
This is the equation of a rightopening parabola.
There is a only one squared variable, so it is a parabola.
The squared variable is y², not x², so the parabola is horizontal.
Put equation into vertex form for horizontal parabola:
x = a(y−k)² + h
Regroup terms
x = 2y²  4y + 5
Factor out the leading coefficient
x = 2(y²  2y) + 5
Complete the square
x = 2(y²  2y + (1)²) + 5  2(1)²
x = 2(y  1)² + 3
This is the equation of a rightopening parabola.