Determine the pH of solutions with each of the following [H3O+]
a. 2.0 x 10^-5 M
Not asking for just the answer but how to do it
a. 2.0 x 10^-5 M
Not asking for just the answer but how to do it
-
pH = -log([H3O+])
pH = -log(2.0x10^-5)
pH = 4.70
pH = -log(2.0x10^-5)
pH = 4.70
-
Take the negative log of the concentration of H3O+.
pH = -log([H3O+])
pH = -log(2.0x10^-5)
pH = 4.70
pH = -log([H3O+])
pH = -log(2.0x10^-5)
pH = 4.70
-
The guy above me is right