A company manufactures computer chips, and it is known that 3% of them are faulty. In a batch of 500 such chips, find the probability that between 1 and 2 percent (inclusive) of the chips are faulty.
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x is bin(500, 0.03)
P(x) = 500Cx * 0.03^x * 0.97^(500-x)
P(5 <= X <= 10) = 0.114033 <----------
P(x) = 500Cx * 0.03^x * 0.97^(500-x)
P(5 <= X <= 10) = 0.114033 <----------
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3/100 = x/500
x = 15
x = 15