Solve for x ---> Logarithms -- HELP PLEASE

how would u solve this? please help

ln (x - 2) + ln (x - 5) = ln (x+ 3)

How do you solve this and what answer do you get?

Thanks

First simplify the left side of the equation using the rule that ln(a) + ln(b) = ln(ab)
ln[(x-2)(x-5)] = ln(x+3)

Next, since both sides are to the ln, you can cancel it by doing e to the ln of that side using the rule e^l[n(x)] = x

e^[ln[(x-2)(x-5)]] = e^[ln(x+3)]
(x-2)(x-5) = (x+3)

And finally, simplify and solve for x!

x^2-7x+10 = x+3
x^2-8x+7 = 0
(x-7)(x-1) = 0

FINAL ANSWER: x = 7, 1

ln((x-2)(x-5))=ln(x+3)

x^2-7x+10=x+3
x^2-8x-7=0 roots of this are : 7 and 1