Solve 3-4i+2ix=3i-(1-i)x

3-4i+2ix=3i-(1-i)x
2ix + (1-i)x = 3i -3 +4i
x ( 2i +1 -i) = 7i -3
x ( i +1) = 7i - 3
x = ( 7i -3) / (i +1)
= ( 7i -3) / (i +1) * ( i-1)/(i-1)
= (7i -3)(i -1) / ( i+1)(i-1)
= ( 7i^2 -7i -3i +3) / ( i^2 -1)
= (- 4 -10i) / (-2)
= 2 + 5i

3-4i+2ix=3i-(1-i)x

3-4i+2ix =3i -x +ix

3 - 7i +x + ix =0

x (1+i) = 7i -3
x = (7i -3) / (1 +i)
answer