How do u solve 9(1-x)^2 need working aswel

9(1-x)^2 is equivalent to 9(1-x)(1-x)

Start with the 1 in the first expression and multiply that by (1-X), so you have 1-X
Then multiply out the -X by the (1-X), so you have -X+X^2 (it becomes positive because you multiplied 2 negatives together).
Now put the two expressions together, so you have 1-X-X+X^2, simplified to 1-2X+X^2, which can also be written as X^2-2X+1.
Now multiply that by 9, so you have 9X^2-18X+9

It's been a long time since I've taken math, but I believe that's how you do it!

9(1- x)^2 = 9(1-x)(1-x) =(9 -9x)(1-x) multipy 9 to each part in the first parenthese
= 9- 9x -9x +9x^2 multiply 9 with 1 and multiply 9 with -x then multiply
-9x with 1 then multipy -9x with -x
= 9x^2 -18x +9 combine -9x and -9x and put the parts in order from
highest power down

9(1-x)(1-x)

9(1 - 1x - 1x + x^2)

9(1 - 2x + x^2)

9 - 18x + 9x^2

9x^2 - 18x + 9

Jen

9(1-x)^2
= 9(1-2x+x^2)
= 9-18x+9x^2