Word proplem maths equations

two cities are 200 miles appar, because of track re laying the train averages 10 miles poer hour less for the h\journey less than normal, the train arrives 40 minuites late, find the normal avergae speed , i got the answres and in my working i got to a ppoint wre i got a wiered quadratic that dosent suite the answer any help!! the answer should be 60mph

another prooplem is when 1 is added the numerator and denomintor of the fraction m/n the new fraction is 3/2 and when 1 is subtracted from the numerator and denominator of the fraction m^2/n^2 the new fraction is 21/8 find possible value of m and n .. i cnat make sense of this question?? the answres should be m=8 and n=5 help!!

Hello

the 2 cities:
use s = v*t: (with v = normal speed mi/h , t = normal time in hours)
and
200 = (v-10)(t+2/3)
---------
solutions: t = 10/3 h
v = 60 m/h
--------------------------------------…
(m+1)/(n+1) = 3/2
and
(m^2-1)/(n^2-1)
------
solutions
m = 8
n = 5

What are your difficulties, the equations, or how to solve them?

Regards

Hello again,
I let this calculate by Wolfram alpha. There is not enough space here to write this down, and you have no email. Solve one equation for one unknown, and put into the other equation. It is a bit lengthy, especially the second equations, but is easy. Otherwise you should mail me.
Ossi

Report Abuse