Shortest distance between a point and a plane

Find the distance between the point (0,0,0) and the plane given by the equation x+2y+3z= 14.

I got square root (14) as the answer.

Is this correct? Thank you.

The perpendicular distance from point (x1,y1,z1,) to plane ax+by+cz=d is
|ax1+by1+cz1-d|/sqrt(a^2+b^2+c^2) and this gives your answer. Well done.