How do you solve a2 + b2 – 2ab – 1

thats a squared plus b squared minus 2ab minus 1

a² - 2ab + b² - 1 =

(a - b)² - 1 =

[(a - b) + 1][(a - b) - 1] =

(a - b + 1)(a - b - 1)

a² - 2ab + b² - 1
can be written as (a - b)² - 1
factor it as a² - b² = (a+b)(a-b)
(a - b)² - (1)² = [(a - b) + 1] [(a - b) - 1]
Answer

Solve it or factor is?

a^2 + b^2 - 2ab - 1
= (a - b)^2 - 1
= (a - b + 1)(a - b - 1)

a² + b² - 2ab - 1
= a² + b² - 2ab - 1²
= a² - 2ab + b² - 1²
= (a - b)² - 1²
= (a - b + 1)(a - b - 1)

solved