How do you find f prime of 2 if f(x) = 4x^2 - 3x

Use the power rule first. Remember, in the power rule, you multiply the coefficient by the exponent, and then subtract one from the exponent. Also remember that x^0 = 1 so -3x will just become -3 because it is multiplied by 1.

f(x) = 4x² - 3x
f '(x) = 8x - 3

Now, substitute a 2 in.

f '(2) = 8(2) - 3
= 16 - 3
= 13

f'(x) = 8x -3
f'(2) = 8*2 - 3 = 13


You just use power rule and plug in the 2 for x.

f '(x) = 8x - 3

f '(2) = 16 - 3 = 13