Okay so this is on probability but i dont get what i have to do here.
You pick two marbles from the bag at the left (4 blues,3 reds,2 greens). You pick the second one without replacing the first one. Find each probability.
23. P(red then blue)
24.P(two blues)
You pick two marbles from the bag at the left (4 blues,3 reds,2 greens). You pick the second one without replacing the first one. Find each probability.
23. P(red then blue)
24.P(two blues)
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23. 3/9 * 4/8 = 1/3 * 1/2 = 1/6 (3 reds out of 9 marbles, then 4 blues out of 8 marbles left)
24. 4/9 * 3/8 = 12/72 = 1/6 (4 blues out of 9 marbles, then 3 blues left out of 8 marbles left)
Jen
ETA: Laughing at the dork below me that totally copied my answer, including my name!
24. 4/9 * 3/8 = 12/72 = 1/6 (4 blues out of 9 marbles, then 3 blues left out of 8 marbles left)
Jen
ETA: Laughing at the dork below me that totally copied my answer, including my name!
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23. 3/9 * 4/8 = 1/3 * 1/2 = 1/6 (3 reds out of 9 marbles, then 4 blues out of 8 marbles left)
24. 4/9 * 3/8 = 12/72 = 1/6 (4 blues out of 9 marbles, then 3 blues left out of 8 marbles left)
Jen
ETA: Laughing at the dork below me that totally copied my answer, including my name!
24. 4/9 * 3/8 = 12/72 = 1/6 (4 blues out of 9 marbles, then 3 blues left out of 8 marbles left)
Jen
ETA: Laughing at the dork below me that totally copied my answer, including my name!
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23. Chance of red = 3/9 = 1/3
Now there are only 8 marbles in the bad with 4 blues
Chance of blue = 4/8 = 1/2
Chance of red then blue = 1/3 * 1/2 = 1/6
24. First blue = 4/9
Second blue = 3/8
For both 4/9 * 3/8 = 1/6
Now there are only 8 marbles in the bad with 4 blues
Chance of blue = 4/8 = 1/2
Chance of red then blue = 1/3 * 1/2 = 1/6
24. First blue = 4/9
Second blue = 3/8
For both 4/9 * 3/8 = 1/6