How do you solve for x in this question? 2secx-1 = 0

Do you change secx to 1/cosx ????

Since: 2.sec(x) - 1 = 0,
then: sec(x) = 1/2.

Since: sec(x) ≡ 1/cos(x),
then: 1/cos(x) = 1/2,
so: cos(x) = 2.
But cos(x) <= ± 1 for ALL values of x.
Hence the original equation, 2sec(x) - 1 = 0, has no real value solutions for x.

Puzzling . . . .
 
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