Find the equation of the smallest positive asymptotes in term of Pi

Find the equation of the smallest positive asymptotes in term of Pi
y=tan2theta

Hello,

y = tan(2x) = sin(2)/cos(2x)

So there is a vertical asymptote every time cos(2x)=0:
cos(2x) = 0
2x = ± π/2 + 2kπ (with k in Z).
x = ± π/4 + kπ (with k in Z).

The smallest positive value of x is then π/4 and the asymptote is:
x = π/4

Logically,
Dragon.Jade :-)