How to solve 3x²+2√6x+2

solve by factorization,by completing the square or by quadratic formula but more preferably by factorization

Discriminant = √[(2√6)^2 - 4 * 3 * 2] = 0
=> 3x^2 + 2√6x + 2 is a perfect square and is
= (√3x + √2)^2

An expression cannot be solved. It can be simplified. If you are meaning to solve the equation
3x^2 + 2√6x + 2 =, then its is
(√3x + √2)^2 = 0
=> x = - √(2/3).

well .. by looking at it , it tells ..

3x² = (√3x)² = a²
2 = (√2)² = b²

and 2√6 = 2.√3.√2 = 2ab

=> 3x²+2√6x+2 = (√3x + √2)²

==> x= -√(2/3)


NOTE : i did these kinds of sums so i could figure out that it was a whole square by looking at the nos.
bt .. i would suggest you to find out the discriminant (b²-4ac) before solving .. which comes out to be 0 .. indicating it has equal roots .. which means it is a perfect square ! :)

you put brackets to break down the sum
3x²+2√6x+2
(3x²+2)(√6x+2)
3+2=5+x²=5x²
5x²√8x
because you don't know what x² is you just have to leave it at that unless in gives you the number for what x² stands for
i don't know if this is right i am just guessing lol

3x²+2√6x+2 =
(x√3 + √2)²
then x = -√2/√3 double root

In given form , question has no mathematical meaning.

Could there be an = sign somewhere?
Could there be a zero somewhere?

I hope you know your lack of brackets has made this thing unreadable. Does the square root only cover the 6? Does it go all the way to the 2?

[root3x}^2+ 2 X root3x X root2 + [root 2]^2
[Root3x + root 2] ^2