Help with simple math function

What is the domain of 4 sq root 3x+7

The domain is simply all numbers that do NOT: Make the denominator zero, or make the expression imaginary, or result in an error of some sort (i.e. ln(-1))

So what would cause your expression to do something like this?

The only limitor here is the square root, so the domain is

D{x|3x+7>=0}

or in normal terms:

The domain ia all real numbers except for when 3x+7>=0

^But you can simplify this to:

The domain is such that x is greater than or equal to -7/3

Ok you can write this equation as (3x+7)^(1/4)

To find domain, find value for x that makes equation 0. You only need to look at the (3x+7).

3x=-7
x=(-3/7)
Sqr root graphs have to always be greater or equal to 0.

So domain is x is equal to or greater than
(-3/7)