Algebra 2 help easy 10 points ? Solve all Radical Equations only 2 left

1. (2x + 3 ) ^ 1 / 2 = 4

2. ( 5x - 5 ) ^ 2 / 3 = 16

1. square both side of the equation

(2x + 3)^2/2 = 4^2
(2x + 3) = 16

subtract 3 from both sides
2x = 16 - 3 = 13

divide both sides by 2
x = 13/2 = 6 1/2

2. raise both sides of the equation by 3/2 (to transform the power on the left side to 6/6 which equals one)
5x - 5 = 16^3/2

take the square root of 16 (=4) and raise it to the 3rd power ....4^3 = 64

5x - 5 = 64

add 5 to both sides to get

5x = 69

divide both sides by 5

x = 69/5 or 13 4/5