Solve the inequality x^2 + 6x -16 < 0

The solution is is in the open interval (A, B) where A is______ and B is _______

x^2 + 6x -16 < 0 ===> (x+8)(x-2) <0 ===>

-8 (-8,2) ===> A is -8 and B is 2


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(x + 8)(x - 2) < 0

______________-8_________2____________
x + 8_____-ve___0___+ve_______+ve_____
x - 2_____-ve_______ -ve___ 0___+ve_______
Product__+ve___0___-ve____0___+ve_____

Solution set = { x : -8 < x < 2 , x Є R }

x^2 + 6x -16

(x + 2)(x - 8)

1. x + 2 < 0

x < -2

2. x - 8 < 0

x < 8

x^2 + 6x -16 < 0 ===> (x+8)(x-2) <0 ===>

-8 (-8,2) ===> A is -8 and B is 2

Hope, It will help you.