How would i find the slope with the line formula of m=y2-y1/x2-x1 with the points (2,-1) and (4,3)? (:

how would i find the slope with the line formula of m=y2-y1/x2-x1 with the points (2,-1) and (4,3)?

Hi dear :)
it is easy your (x1 , y1) = (2 , -1)

(x2 , y2) = (4 , 3) so put these variables in your slope formula :)
m= 3-(-1) / 4-2
m=2

just as it says in your formula o.o you take the y coordinate of the second point, subtract the y-coordinate of the first point and divide it by the number where you did the same with the x-coordinates

a point is written like this
(x, y)

so, (2, -1) means x-coordinate = 2 y-coordinate = -1
and (4, 3) means x-coor. = 4, y-coor. = 3

it doesn't matter which one you design as point 1 or 2 as long as you stick by it

so y2-y1/x2-x1 if (2, -1) is point 1
would be
3-(-1) / 4-2 = 4/2 = 2

to see how it doesn't matter which one you design as point 1 or 2 let's switch that around
point (4,3) is now point 1

y2-y1/x2-x1
-1 - 3 / 2 - 4 = -4/-2 = 4/2 = 2

m= 3-(-1)/4-2 = m= 4/2 m=2