How do I write this expression as a complex number is standard form? *10 POINTS FOR BEST ANSWER~!!!*

(2i)(1-4i)(1+i)

i= imaginary number

Thank youuu :D

Multiply it out as you would for a non complex term.
(2i)(1-4i)(1+i)
=(2i+8)(1+i)
=2i-2+8+8i
=6+10i

Multiply everything out.
Notes:
1.) ^ stands for "raised to the _ power"
2.) A positive number times a negative number is always negative.
3.) When you multiply two similar variables (i), it will be i^2.
4.) When you multiply a constant and variable with a constant and variable, such as 2x times 3x, you multiply the bases (2 times 3= 6) and you also multiply the variables (x times x= x^2). Your answer would be 6x^2.
5.) Each time you multiply a variable times itself, it's exponent (^) is raised by one. i times i equals i^2, and i^2 times i equals i^3.

Step 1: Start with the first two quantities using the distributive property.
(2i)(1-4i)
2i times 1 equals 2i.
2i times -4i equals -8i^2
Put your two answers together. (2i)(1-4i)= 2i -8i^2

Step 2: Use the distributive property and multiply out -8i^2 to the third quantity.
2i -8i^2(1+i)
-8i^2 times 1 equals -8i^2.
-8i^2 times i equals -8i^3
Put them together to get -8i^2 -8i^3.

Step 3: Final answer.
After multiplying out -8i^2, you are left with 2i -8i^2 -8i^3.