Please help me. Show that.

f(x)=|x|+1
this is even funtion, So why?
And f(x)=|x-1| this is even or odd?

A function is said to be even function if f(-x)=f(x)
And if f(-x)=-f(x) it is said to be an odd function
here,
f(x)=lxl+1
f(-x)=l-xl+1
mod of any negative no is always positive
so, f(-x)=lxl+1=f(x)
therefore it is even
and
f(x)=lx-1l
substituting x by -x
f(-x)=l-x-1l
f(-x)=l-(x+1)l =lx+1l
which is not equal to f(x)
therefore it is neither even nor odd