Find a 3rd degree polynomial equation with real coefficient and express it in expanded form

then number given are: 2, 1 + i

please show your work.

complex zeros are found in conjugate pairs
so
y = (x - 2)(x - (1 + i))(x - (1 - i))
then
expand the complex pair first:
y = (x - 2)(x² - (1 - i)x - (1 + i)x + (1 - i²)) ← (a + b)(a - b) = a² - b²
   = (x - 2)(x² - x + ix - x - ix + (1 + 1)) ← i² = -1
   = (x - 2)(x² - 2x + 2)
   = x(x² - 2x + 2) - 2(x² - 2x + 2) ← distributive property
   = x³ - 2x² + 2x - 2x² + 4x - 4
   = x³ - 4x² + 6x - 4

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