Find all solutions of the equation in the interval [0,2pi] for Cotθ=2

If there is more than one solution, separate them with commas.
Do not round any intermediate computations, and round your answer(s) to the nearest hundredth.

I seriously need help with this

cotθ = 2
1/tanθ = 2
tanθ = 1/2

θ = arctan(1/2), arctan(1/2) + π
θ = 0.463647609, 3.605240263

ans: 26.565 degrees and 206.565 degrees.

Cot X = 2 is identical to Tan X = 1/2. This occurs for X = 26.565 degrees in the first quadrant and an angle of (180 + 26.565) = 206.565 degrees in the third quadrant. The tangent and cotangent are both negative in the second and fourth quadrant so there are no solutions in these quadrants.

Cot(theta) = 2
1/tan(theta) = 2
tan(theta) = 1/2 or 0.5 so theta = 26 degrees 31 minutes
tan(theta) is positive in the first and third quadrants, i.e. between 0 and 90 degrees (pi/2) and between 180 and 270 degrees (pi and (3/2)pi

So theta = 26 degrees 31 minutes in the first quadrant and 180+26 31 minutes = 206 degrees 31 minutes in the third quadrant.

tanθ = 1/2 ---> θ = 0.4636 or 3.60