What is the normal vector of this plane equation? x + 2*x - 4 = 0

x + 2*x - 4 = 0

= 3x - 4 = 0

= 3x + 0y + 0z - 4 = 0

Normal vector = < 3, 0, 0 > or < 1, 0, 0 >

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Using new information:

x + 2*z - 4 = 0

= x + 0y + 2z - 4 = 0

Normal vector = < 1, 0, 2 >

x + 0y + 2z = 4

Normal vector is (1, 0, 2). Just read off the coefficients of x, y and z in that order.

ant a clue