According to the following table, what is (3f+2g)(1) and (fog)(-1)

Given the table below evaluate the following:
x: -3,-2,-1,0,1,2,3,4,5
f(x): 10,20,30,40,50,60,70,80,90
g(x): -1,-2,-3,-4,-5,-6,-7,-8,-9

A) (3f+2g)(1)
B) (fog)(-1)

A) (3f+2g)(1) = 3f(1) + 2g(1) = 3*50+2*(-5) = 140
B) (fog)(-1) = f(g(-1)) = f(-3) = 10