In a previous question I've asked how to integrate 3 / (x-1). They said 3 ln (x-1)
Can you explain to me how it's 3 because it's the derivative of 3 , 0?
Can someone explain this?
Can you explain to me how it's 3 because it's the derivative of 3 , 0?
Can someone explain this?
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Yes the derivative of 3 is 0, but we're integrating not taking derivatives.
Constant rule of integration
∫ kf(u)du = k ∫ f(u)du constants can be removed from the integral and put in front
example
∫ 3xdx = (3/2)x^2 + c
∫ 3xdx = 3 ∫ xdx = (3)(x^2)/2 + c = (3/2)x^2 + c
Constant rule of integration
∫ kf(u)du = k ∫ f(u)du constants can be removed from the integral and put in front
example
∫ 3xdx = (3/2)x^2 + c
∫ 3xdx = 3 ∫ xdx = (3)(x^2)/2 + c = (3/2)x^2 + c
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3* 1/(x-1). 3 is the constant here and it stays in differientation and integration.