5x^2 = 3x -2
Somehow i ended up with 3 +/- (the square root of 31) / 10
I did.. something wrong.
Somehow i ended up with 3 +/- (the square root of 31) / 10
I did.. something wrong.
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5x^2 = 3x - 2 rearrange into a quadratic in standard form
5x^2 - 3x + 2 = 0
a = 5
b = - 3
c = 2
( - (- 3) +/- √((- 3^2) - (4)(5)(2) )) / (2(5))
( 3 +/- √( 9 - 40) )/ 10
(3 +/- √(- 31)) / 10 --> 31 is prime, so remove √(-1) = i
(3 +/- i√(31))/10
5x^2 - 3x + 2 = 0
a = 5
b = - 3
c = 2
( - (- 3) +/- √((- 3^2) - (4)(5)(2) )) / (2(5))
( 3 +/- √( 9 - 40) )/ 10
(3 +/- √(- 31)) / 10 --> 31 is prime, so remove √(-1) = i
(3 +/- i√(31))/10