How do you solve this equation for x? It looks so easy, but I'm stumped. b(to the x power) = c(to the x + a )
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How do you solve this equation for x? It looks so easy, but I'm stumped. b(to the x power) = c(to the x + a )

[From: ] [author: ] [Date: 12-05-21] [Hit: ]
......
I can't get x by itself no matter what I do!

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b^x = c^(x + a)

b^x = c^x c^a

b^x/c^x = c^a

(b/c)^x = c^a

log (b/c)^x = log c^a

x log (b/c) = a log c

x = a log c/[log (b/c)]

x = a log c/[log b - log c].
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