Use the properties of inverse functions to evaluate the expression.
sin[arcsin(-0.2)] can anyone please help?
sin[arcsin(-0.2)] can anyone please help?
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sin(sin^-1(-0.2)) = -0.2
there is no manipulation of the angle necessary because all domain and range issues are satisfied
there is no manipulation of the angle necessary because all domain and range issues are satisfied
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It is -0.2. Think of it like the sine and arc sine cancle each other out sine they are opposite leaving only the -0.2
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-0.2
the arcsin function will take it one way but the sin on the outside will bring it right back to -0.2
the arcsin function will take it one way but the sin on the outside will bring it right back to -0.2