Precal help - trigonometric ratio

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I have to do question 68, can someone break this down in laymen terms?

cos(330) = cos(360-30) = cos(30) since cos is positive in fourth quadrant

= √3/2


csc(-225) = 1 / sin(-225) = 1/- sin(225) = -1 / sin(180 + 45) = -1/ - sin(45) [ sine is negative in 3rd quadrant]

= 1/sin(45) = √2

[all angles used in degrees]

68a)
cos 330 = cos 30 = sqrt(3)/2
68b)
csc -225 = 1/sin -225 = 1/sin 135=
1/sin 45 = 2/sqrt(2) = sqrt(2)