String’s fundamental frequency

A stringed instrument has a maximum string
length of 0.5 m and is tuned so that a wave
travels along the string at 120 m/s.
What is the string’s fundamental frequency
at this length and wave speed?
Answer in units of Hz.

Hello

c = velocity of wave
F = tension
ρ = density
q = cross section area
f = frequency
n = 1, 2, ..

c = √(F/(ρ*q) and
fn = n/2L * √(F/(ρ*q)

so
fn = n*c/((2L)
f1 = 1*120/(2*0,5) = 120 Hz (= fundamental frequency)

Regards