Hi need help with energy, momentum and Compton effect, quantum mechanics? please
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Hi need help with energy, momentum and Compton effect, quantum mechanics? please

[From: ] [author: ] [Date: 11-05-25] [Hit: ]
you must define the initial wavelength, the final wavelength, the momentum of the electron after the collision and the scattering angle. Is good to know that a photons momentum is given byp=h/lambda.......
So the change in photon momentum is [(h / λ) - (h / (λ + ∆λ)]

So,
Before collision
Total horizontal momentum = (h/λ) + 0
Total vertical momentum = 0 + 0

After collision
Total horizontal momentum = [(h / λ) - (h / (λ + ∆λ)] cos Ѳ + m(e)v cos α
Total vertical momentum = [(h / λ) - (h / (λ + ∆λ)] sin Ѳ - m(e)v sin α

So, applying the conservation of momentum we get
Horizontally
(h / λ) = [(h / λ) - (h / (λ + ∆λ)] cos Ѳ + m(e)v cos α

Vertically

0 = [(h / λ) - (h / (λ + ∆λ)] sin Ѳ - m(e)v sin α
so,
m(e)v sin α = [(h / λ) - (h / (λ + ∆λ)] sin Ѳ

Hope you can follow this!

-
The expression is

E = sqrt (m^2*c^4 + p^2*c^2) where m is the rest mass.

You have then:

h^2 * f^2 = h^2 * c^2 / lambda^2 = m^2 * c^4 + p^2 * c^2 = >

= > p^2 = h^2 / lambda^2 - m^2 * c^2 => p = +/- sqrt ( h^2 /lambda^2 - m^2 * c^2).

For the second, you must define the initial wavelength, the final wavelength, the momentum of the electron after the collision and the scattering angle. Is good to know that a photon's momentum is given by
p=h/lambda.
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